1 ) What is total number of radical and angular nodes present in 5f orbital ?
1 ) What is total number of radical and angular nodes present in 5f orbital ?
Solution : -
Radical and angular nodes : -
Region where electron density in an orbital is zero .
5f orbital : -
Principal quantum number is number of shells . So , n = 5 .
Azimuthal quantum number is number of sub shells . So , L = 3 .
∴ Azimuthal quantum number for different sub shells : -
s = 0 , p = 1 , d = 2 , f = 3 .
So , now we can find radical and angular nodes : -
Radical nodes : — n — L — 1 = 5–3–1 = 1 .
Angular nodes : — L = 3 .
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2 ) The number of nodes for 4f orbital is : -
A ) 3 , B ) 4 ,
C ) 6 , D ) None of these ,
Correct Answer : — A ) 3 ,
Solution : -
For 4f : — n = 4 , L = 3 .
So , number of angular nodes = L = 3 .
Number of radial nodes = n — L — 1 = 4–3 -1 = 0 .
So , total number of nodes =
